Here is a copy of today's note. Unfortunately we did not get to discuss the benchmark thoroughly.
Showing posts with label unit 2. Show all posts
Showing posts with label unit 2. Show all posts
Wednesday, January 16, 2008
Tuesday, January 15, 2008
Thursday, January 10, 2008
Wednesday, January 9, 2008
Changing Division to Multiplication
To turn a division problem to a multiplication, you need to flip the fraction.

In order to turn this problem into a multiplication problem, you need to turn this fraction upside down, by having the fraction as on 2/5, flip it to get 5/2. Then change the sign to multiplication. Solve the problem.
In order to turn this problem into a multiplication problem, you need to turn this fraction upside down, by having the fraction as on 2/5, flip it to get 5/2. Then change the sign to multiplication. Solve the problem.
Tuesday, January 8, 2008
Friday, January 4, 2008
Friday, December 21, 2007
Addition to Subtraction
To change addition to subtraction what you have to do is leave the starting number the same but change the sign of all numbers after that to the opposite sign. Also change the addition sign to subtraction because subtracting a negative is just the same as adding a positive so the sum will still remain the same.
Example : 4 + 5 = 8
4 - -5 = 8
Example : 4 + 5 = 8
4 - -5 = 8
Problem -6-50
-6-50
To solve this problem I subtracted -50 from -6.
When I subtracted these integers I go -56.
To solve this problem I subtracted -50 from -6.
When I subtracted these integers I go -56.
Combining Terms: Patricia Parker Number 5
6a - 5 - 4-2a + 7=8a -16
First you add 6a+ 2a= 8a
Then You add -5 + -4 + -7+-16
You add the same varables together and there numbers.
Like the 2a and the 8a are to be added because they have the same varaibles.
First you add 6a+ 2a= 8a
Then You add -5 + -4 + -7+-16
You add the same varables together and there numbers.
Like the 2a and the 8a are to be added because they have the same varaibles.
Labels:
Patricia,
scribe post,
Test Review,
unit 2
Thursday, December 20, 2007
Darnell's way of Multiplying fractions
When you multiply a fraction like 3/4 * 2/3 you would first multiply the numerator and then the denomenator so that the answer would be 6/12 and to make that a whole number all you have to do is divide six into twelve to get 2.
5 * 5/4
5 * 5/4
5/1 * 4/5
20/5=4Robbie's Associative Property Blog
The only way to explain the Associative Property is to move the parenthesis from one pair of numbers to another ex. a+(b+c)=(a+b)+c
Distributive Property
Distributive Property
x -(4x+5)
Distributive Property is an algebra property that is used to multiply a single term and two or more terms inside a set of parentheses. When I do distributive property I know to multiply the outside numbers by the inside numbers. That’s all you really need to know. As you read on I will give you same examples to give you an idea on how to do distributive property.
For Example:
This is not the right way to do this problem.
Step 1. 8(3+7)
Step 2. 8*3+7
Step 3. 24+7
Step 4. =31
This is the right way to do this problem.
Step 1. 8(3+7)
Step 2. 8*3=24
Step 3. 8*7=56
Step 4. 24+56
Step 5. =80
For the problem x-(4x+5) you would think you would have to multiply the (X) with the two numbers in the parentheses which is 4x+5. A lot of people make this common mistake. In fact x-(4x+5) you don’t multiply the numbers in the parentheses with (X) but, with the (-).
For Example: you can rewrite the problem like this.
Step 1. x+-1(4x+5)
* only use the -1 in the multiplication
Step 2. -1*4x=-4x
Step 3. -1*5= -5
Step 4. Rewrite as 1x+-4x-5
Step 5. You get -3x-5
x -(4x+5)
Distributive Property is an algebra property that is used to multiply a single term and two or more terms inside a set of parentheses. When I do distributive property I know to multiply the outside numbers by the inside numbers. That’s all you really need to know. As you read on I will give you same examples to give you an idea on how to do distributive property.
For Example:
This is not the right way to do this problem.
Step 1. 8(3+7)
Step 2. 8*3+7
Step 3. 24+7
Step 4. =31
This is the right way to do this problem.
Step 1. 8(3+7)
Step 2. 8*3=24
Step 3. 8*7=56
Step 4. 24+56
Step 5. =80
For the problem x-(4x+5) you would think you would have to multiply the (X) with the two numbers in the parentheses which is 4x+5. A lot of people make this common mistake. In fact x-(4x+5) you don’t multiply the numbers in the parentheses with (X) but, with the (-).
For Example: you can rewrite the problem like this.
Step 1. x+-1(4x+5)
* only use the -1 in the multiplication
Step 2. -1*4x=-4x
Step 3. -1*5= -5
Step 4. Rewrite as 1x+-4x-5
Step 5. You get -3x-5
Zero Product Property
1. (x+5) (x-2)= 0
~ANSWER~
x=-5 or x= 2
2. x^2+3x-10= 0

~ANSWER~
x= - 5 or x=2
3. (x+5)(x-4) =0
~ANSWER~
x= -5 or x= 4
HELP/ NOTES
~ANSWER~
x=-5 or x= 2
2. x^2+3x-10= 0

~ANSWER~
x= - 5 or x=2
3. (x+5)(x-4) =0
~ANSWER~
x= -5 or x= 4
HELP/ NOTES
Zero - Product Property
Definition of Zero - Product Property
Zero - Product Property states that if the product of two factors is zero, then at least one of the factors must be zero.
Examples of Zero - Product Property
- If xy = 0, then x = 0 or y = 0.
Wednesday, December 19, 2007
Marshall
3/5x - 3/4 = 1/2x +3/4
Find a common denominator: 20
Multiply both sides by 20: 3x - 3 = 1x + 3
Subtract 1x from both sides: 2x - 3 = 3
Add 3 to both sides: 2x = 6
Divide both sides by 2: X = 3
Find a common denominator: 20
Multiply both sides by 20: 3x - 3 = 1x + 3
Subtract 1x from both sides: 2x - 3 = 3
Add 3 to both sides: 2x = 6
Divide both sides by 2: X = 3
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